Physics, 02.01.2020 19:31 Reebear1447
Aball is thrown up into the air with an initial velocity of 64 ft/sec. the ball is 4 ft above the ground when it is released. its height, in feet, at time t seconds is given by: h(t) = −16t^2 + 64t + 4. what is the time when it reaches its maximum height?
Answers: 1
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Aball is thrown up into the air with an initial velocity of 64 ft/sec. the ball is 4 ft above the gr...
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