If water is leaking from a certain tank at a constant rate of 1,200 milliliters per hour, how many seconds does it take for 1 milliliter of water to leak from the tank?

It will take 3 seconds for 1 milliliters of water to leak from the tank.

Explanation:

The rate of leak = volume of water/Time

Q = V/t equation 1

making t the subject of the equation above,

t = V/Q Equation 2.

where Q = rate of leak, V = volume of water, t = time

Given: Q = 1200 milliliters per hour, V = 1 milliliters.

Substituting these values into equation 2

t = 1/1200

t = 0.00083 hours.

If  I hours = 3600 seconds,

Then, 0.00083 hours = 0.00083×3600 seconds

= 3 second.

Therefore it will take 3 seconds for 1 milliliters of water to leak from the tank.

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )