Acrate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 14.0 n.
(a) what acceleration is produced?
(b) how far does the crate travel in 10.0 s?
(c) what is its speed at the end of 10.0 s?

Answer

given,

mass of crate = 32.5 Kg

horizontal force  = 14 N

initial speed, u = 0 m/s

a) acceleration produced = ?

we know,

F = m a

      a = 0.431 m/s²

b) using equation of motion

    t = 10 s

        s = 21.54 m

c) again using equation of motion

     v = u + at

     v = 0 + 0.431 x 10

     v = 4.31 m/s

a.) is the correct answer.

explanation:

hujjujddf