On april 15, 1912, the luxury cruise liner titanic sank after running into an iceberg. what was the cruise liner’s speed when it collided with the iceberg if it had a mass of 4.23 x 108 kg ship and a momentum of 4.9 x 109 kg·m/s?

The cruise liner’s speed when it collided with the iceberg if it had a mass of 4.23 x 108 kg ship and a momentum of 4.9 x 109 kg·m/s is v= 11.584 m/s

Explanation:

Given :

The cruise liner’s speed when it collided with the iceberg has a

Mass (m) = 4.23 x 108 kg  and

Momentum (p) = 4.9 x 109 kg m/s

To calculate the momentum,

We need to use the formula of a momentum

Momentum = Mass x Velocity ( p = m v )

as we need to find the velocity the formula becomes

velocity = momentum / mass

v = p / m

= (4.9 x 109 kg m/s) / (4.23 x 108 kg)

v= 11.584 m/s

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.