A3.00 kg toy falls from a height of 1.00 m. what will the kinetic energy of the toy be just before the toy hits the ground

K E = 29.4 J

Explanation:

given,

mass of the toy = 3 Kg

height of fall = 1 m

acceleration due to gravity (g)= 9.8 m/s²

Kinetic energy of the toy = ?

Using conservation of energy

Potential energy of the toy at height h will be converted into  into kinetic energy .

P E = K E

K E = m g h

K E = 3 x 1 x 9.8

K E = 29.4 J

Hence, the kinetic energy of the toy before it hit the ground is equal to K E = 29.4 J

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.