Crickets chirpy and milada jump from the top of a vertical cliff. chirpy drops downward and reaches the ground in 2.70 s, while milada jumps horizontally with an initial speed of 95.0 cm/s. how far from the base of the cliff will milada hit the ground? ignore air resistance.

Explanation:

Given

Time taken to reach ground is

Malda initial velocity

Let h be the height of Cliff

using

where, u=initial velocity

t=time

In first case chirpy drop downward thus u=0

For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]

time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by

i think the answer is a and b

i wish you luck

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft