Find the work done by a force of 20 lbs acting in the direction north 50 degrees west in moving an object 4 feet due west?

Workdone = 61.28ft.lbs

Workdone in moving the object 4ft due west is 61.28ft.lbs

Explanation:

Given;

Force = 20lbs

Direction = N 50° W

Distance moved = 4ft

Workdone = Force × distance

W = fd

But f in this case is

Force due North = fcos50

Force due west = fsin50

Since we are to find the workdone due west then

W = fsin50 × d = fdsin50

W = 20lbs × 4ft × sin50

Workdone = 61.28ft.lbs

i was thinking more like reflects green light, just not sure

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get