Acar starting from rest has an acceleration 0.3m/s2 calculate the velocity and distance travelled by this car after 2 minutes

2160 m, 36 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 0.3 m/s²

t = 2 min = 120 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (120 s) + ½ (0.3 m/s²) (120 s)²

Δx = 2160 m

v = at + v₀

v = (0.3 m/s²) (120 s) + (0 m/s)

v = 36 m/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle