Alaser beam strikes a plane's surface with an angle of52.
what is the angle between the incident ray and thereflected
ray?

Angle between incident ray and reflected ray will be 104°

Explanation:

We have given angle of incidence = 52 °

From law of reflection angle of incidence will be equal to angle of reflection

So angle of reflection will be also 52°

We have to find the angle between incident ray and reflected ray

As the incidence angle and reflected angle both is from normal of the surface and opposite to each other

So angle between incident ray and reflected ray will be 52°+52° = 104°

f=ma newton

f=100x2.5=250n

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2