Light of wavelength 550 nm falls on a
slitthat is 3.00x10^-3mm wide. how far from the central maximumwill
the first diffraction maximum fringe be if the screen is
10.0maway?

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

(1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum () are small compared to the distance between the screen and the slit (x), we can approximate , using this on (1):

solving for y

Note that is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find , add them and divide by two:

gas and liquid

i think it would be 5