Superman leaps in front of lois lane to save her from a
volleyof bullets. in a 1 minute interval, an automatic weapon
fires160 bullets, each of mass 8.0 g, at450 m/s. the bullets strike
his mightychest, which has an area of 0.71m2. find the
average force exerted on superman's chestif the bullets bounce back
after an elastic, head-on collision. express your anwser in
n.

Explanation:

We will use the relationship between impulse and momentum.

We are considering the change of momentum of Superman at the moment of collision.

This force is distributed throughout Kal-El’s chest. So, the average force is

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft