Ahorizontal spring is lying on a frictionless surface. oneend
of the spring is attaches to a wall while the other end isconnected
to a movable object. the spring and object are compressedby 0.077
m, released from rest, and subsequently oscillate back andforth
with an angular frequency of 15.3 rad/s. what is the speed ofthe
object at the instant when the spring is stretched by0.033
m relative to its unstrained length?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j