Amagnet in the form of a cylindrical rod has a length of5.00 cm and a diameter of 1.00 cm. it has a uniform magnetization of5.50 x 10^3 a/m. what is its magnetic dipole moment?

The magnetic dipole moment = 0.0216 J/T

Explanation:

Magnetic dipole moment: The mathematical expression for the magnetic dipole moment of a cylindrical rod is as shown below.

μ = MV Equation 1

Where μ = magnetic dipole moment, M = magnetic field, V = volume of the cylindrical rod.

But

V = πr²L Equation 2

Where r = radius of the cylindrical rod, L = length of the rod.

Substituting equation 2 into equation 1

μ = Mπr²L Equation 3.

given: M = 5.50×10³ A/m, r = d/2 = 1/2 = 0.5 cm = 0.005 m, L = 5 cm = 0.05 m

Constant: π = 3.143.

Substituting these values into equation 3

μ = 5.5×10³×3.143×(0.005)²×0.05

μ = 0.0216 J/T

Thus the magnetic dipole moment = 0.0216 J/T

.) the observation by semmelweis that more mothers died of childbed fever when their doctors also worked in the morgue

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.