Two steel guitar strings have the
samelength. string a has a diameter of 0.50mm and is under 440.0 n
oftension. string b has a diameter of 1.0 mm and is under a
tensionof 820.0 n. find the ratio of the wave speeds, va/vb, in
these twostrings.

Explanation:

given,

diameter of string A = 0.5 mm

tension in string A = 440 N

diameter of string B = 1 mm

tension in string B = 820 N

wave speed =

M is the linear density that is mass per unit length =mass / length

 mass = density x volume

from the above equation

now,

ratio of the wave speed Va/Vb is 1.47

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.