Araindrop, mysteriously, falling on the moon, hits thesurface
at 57.4 m/s. the moon's gravity is 1.6 m/s/s. determine thetime
that the drop is falling.

The time that the drop is falling =35.875 s

Explanation:

Using one of newton's equation of motion

g = V-u/t Equation 1

Where V = final velocity, u = initial velocity, g = acceleration due to gravity of the moon, t = time.

Note: for a dropping object, u = 0 m/s

g = V/t Equation 2

making t the subject of equation 2 above

t = V/g Equation 3

Given: V= 57.4 m/s, g = 1.6 m/s²

Substituting these values into equation 3

t = 57.4/1.6

t = 35.875 s

t = 35.875 s

The time that the drop is falling = 35.875 s

i don't know that i agree with that but what's the question ?