A19 kg solid disk of radius0.44 m is rotated about an
axisthrough its center. if the disk accelerates from rest to an
angularspeed of 2.5 rad/s while rotating1.0 revolutions, what net
torque isrequired?

0.915 Nm

Explanation:

1 revolution = 2π rad

We can use the following equation of motion to find out the acceleration acting on the disk

where = 0 rad/s is the initial velocity of the can when it starts from rest, is the angular distance traveled, is the angular acceleration of the disk, which we care looking for:

The moment of inertia of the solid disk is:

where m is the mass and R is the radius of the disk

The net torque applied is

d.7.5cm is your answer

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: