For general projectile motion, the horizontal component
ofa projectile's acceleration
remains a
non-zeroconstant.
increases as a
functionof time squared.

continuouslyincreases.

continuouslydecreases.
is zero.

Zero.

Explanation:

In the general projectile motion there is only one component of acceleration which is in the vertical direction.There is no any acceleration in the horizontal direction.As we know that horizontal component of the velocity is remains constant in the projectile motion.

Therefore we cans say that in the projectile motion ,the acceleration in the horizontal direction is zero.

Therefore the answer will be zero.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft