What is most nearly the frictional force between the 78 kg block and the ramp? the coefficient of static friction is 0.2

Answer

given,

mass of the block = 78 Kg

coefficient of static friction =  0.2

Ramp is inclined so, assuming the angle of ramp be equal to 40°.

Frictional force = μs N...........(1)

Normal force,

N = m g sin θ

now, putting value of N in equation (1)

f = μs m g sin θ

g is acceleration due to gravity, g = 9.8 m/s²

f = 0.2 x 78 x 9.8 x sin 40°

f = 98.27 N

hence, the frictional force acting between block and ramp is equal to f = 98.27 N

the results is a decrease in air temperature with an increase of altitude.

explanation:

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.