The driver of a car traveling at 22.8 m/s applies the brakes and undergoes a constant deceleration of 2.95 m/s 2 . how many revolutions does each tire make before the car comes to a stop, assuming that the car does not skid and that the tires have radii of 0.2 m? answer in units of rev.

70 revolutions

Explanation:

We can start by the time it takes for the driver to come from 22.8m/s to full rest:

The tire angular velocity before stopping is:

Also its angular decceleration:

Using the following equation motion we can findout the angle it makes during the deceleration:

where = 0 m/s is the final angular velocity of the car when it stops, = 114rad/s is the initial angular velocity of the car = 14.75 rad/s2 is the deceleration of the can, and is the angular distance traveled, which we care looking for:

or 440/2π = 70 revelutions

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.