Physics, 10.01.2020 06:31 michaelmonroe9105

A) a boy is riding on a merry-go-round that rotates at a constant speed. if the merry-go-round makes 3.0 revolutions in 6.0 seconds. what is its angular speed in revolutions/second and in radians/second?

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Answer from: aliyahgregory

Angular speed = 0.5 revolutions/second = 3.14 rad/s

Explanation:

a) The merry-go-round makes 3.0 revolutions in 6.0 seconds

Time taken for 3 revolutions = 6 s

Time taken for 1 revolution = 6÷3 = 2 s

That is period, T = 2 s

We know that

$\texttt{Angular speed},\omega =\frac{2\pi }{T}$

Substituting

$\texttt{Angular speed},\omega =\frac{2\pi }{2}=3.14rad/s\\\\\texttt{Angular speed},\omega =\frac{2\pi }{2\times 2\pi}=0.5revolutions/s$

Angular speed = 0.5 revolutions/second = 3.14 rad/s

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

The answer would be a) -80of

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A) a boy is riding on a merry-go-round that rotates at a constant speed. if the merry-go-round makes...

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