Achild and a shed with a combined weight of 50.0kg slide down a frictionless hill that is 7.3m high. if the sled starts from the rest, what is its speed at the bottom of the hill answer

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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show the wavelengths of a wave. show the crests of a wave.

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we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer