You place a +1.00 mc charged object in an electric field of 900 n/c that points due east. determine the magnitude and direction of the force on the object.

0.9 N, east

Explanation:

charge, q = 1 mC = 0.001 C

Electric filed, E = 900 N/C due east

Force, F = q E

F = 0.001 x 900

F = 0.9 N

The direction of force is same as the direction of electric field as the charge is positive in nature. So, the direction of force is also east.

real, smaller and upside-down.   so the answer should be b.

small = small current large mag large current