How much energy is required to melt 2.5 moles of ice as 0.0 degrees celsius to liquid water at 0.0 degrees celsius

15 kJ

Explanation:

The latent heat of water at 0°C is 334 J/g.

1 mole of water is 18 g.

m = 2.5 mol × 18 g/mol

m = 45 g

q = mL

q = (45 g) (334 J/g)

q ≈ 15,000 J

It takes about 15 kJ.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.