0.235 moles of a diatomic gas expands doing 205 j of work while the temperature drops 88 k. find q.? (unit=j)

The heat exchange in the given process = -806.79 J

Explanation:

0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K.

Number of moles , n = 0.235

Temperature difference = 88 K

According to conservation of energy,

ΔQ = ΔU + ΔW

We are given the amount of work done and we have to find the heat exchange in the process.

= = 29.1

ΔU = ΔT

ΔU = = -601.79 J

Work done by the gas = -205 J

ΔQ = ΔU + ΔW

Substituting the values,

ΔQ = -601.79 + -205 = -806.79 J

The heat exchange in the given process = -806.79 J