An ideal gas is at 29 ∘c. the gas is cooled, reducing the thermal energy by 10.0%. what is the new temp?

The new temperature will be "26.1°C".

Given:

Initial temperature,

Reduced thermal energy,

The reduction will be:

=

=

hence,

The new temperature will be:

=

=

=

Thus the above answer is right

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26.1°C

Explanation:

Initial temperature of an ideal gas is 29°C. If the thermal energy is reduced by 10% after cooling, the temperature of the gas has reduced by (10% of 29°C)

= 0.1×29

= 2.9°C

The new temperature = initial temperature - reduction

= 29°C - 2.9°C

= 26.1°C