An object undergoing simple harmonic motion takes 0.23 s to travel from one point of zero velocity to the next such point. the distance between those points is 32 cm. (a) calculate the period of the motion.

Period of motion is 0.46 sec

Explanation:

Object is undergoing SHM means object is moving from left to right and then right to left in a specific time called time period. As given object moves from left to right is 0.23 sec which is time for half cycle. Time period for one complete cycle is then

T=2t

T=2(0.23)

T=0.46 sec

Frequency of oscillation would be then

Maximum amplitude of oscillation is the mid point of between left and rght end point:

what is the actual question though?