If a spring with a spring constant k = 10 n/m is stretched from its equilibrium position by 0.1 m, and released, what would be the maxi- mum kinetic energy at any time in its motion? neglect friction.1. 0.025 j2. 0.1 j3. not enough information given4. 0.05 j5. 1 j

4

Explanation:

Given

spring constant

if it is stretched 0.1 m from equilibrium position

If the spring is at maximum extension then the Elastic Potential Potential energy is maximum and is equal to Total energy of the system

When the spring is at equilibrium , total energy will be equal to kinetic energy

So maximum kinetic Energy is equal to

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it