Ablock of mass m is undergoing shm on a horizontal, frictionless surface while attached to a light, horizontal spring. the spring has force constant k, and the amplitude of the shm is a. the block has v = 0, and x = +a at t = 0. it first reaches x = 0 when t=t/4, where t is the period of the motion.

a) in terms of t, what is the time t when the block first reaches x=a/2?

b)the block has its maximum speed when t=t/4. what is the value of t when the speed of the block first reaches the value vmax/2?

c)(hidden. will ask in comments)

The time t when the block first reaches half the amplitude is .

The value of t when the speed of the block first reaches half of its maximum value is .

The general wave equation is given as;

x = A cos ω t

The time when the block reaches x = A/2

The value of t when the speed of the block first reaches half of its maximum value;

Learn more about period of SMH here:

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.