Aplane traveling horizontally at 120 m/s over flat ground at an elevation of 3610 m must drop an emergency packet on a target on the ground. the trajectory of the packet is given by xequals 120t, yequals minus4.9tsquaredplus3610, for tgreater than or equals 0, where the origin is the point on the ground directly beneath the plane at the moment of the release. how many horizontal meters before the target should the packet be released in order to hit the target? set up an equation involving t that could be solved in order to find out how long it takes the packet to reach the ground after being released.

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.