Two particles, each having a mass of 3.0 mg and having equal but opposite charges of magnitude 5.0 nc, are released simultaneously from rest when the two are 5.0 cm apart. what is the speed of either particle at the instant when the two are separated by 2.0 cm?

Explanation:

Given

mass of  particles

charges on particles are

initial distance between them

Final distance between them

Initial Energy at particle is

=Kinetic Energy +Electrostatic Potential energy

initial velocity is zero so

Final Energy

Conserving Energy

50 inches should be the resultant vector

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s