Consider two point particles that have charge +e, are at rest, and are separated by 2.7 x 10-15 m.

1) how much work was required to bring them together from a very large separation distance? kev

2) if they are released, how much kinetic energy will each have when they are separated by twice their separation at release? kev

3) the mass of each particle is 1.00 u (1.00 amu). what speed will each have when they are very far from each other? m/s

Explanation:

q1 = q2 = e = 1.6 x 10^-19 C

d = 2.7 x 10^-15 m

1. Work done is equal to the potential energy stored between the two charges.

The formula for the potential energy is given by

By substituting the values

U = 8.53 x 10^-14 J

So, the work done is 8.53 x 10^-14 J.

(2) d = 2 x 2.7 x 10^-15 m = 5.4 x 10^-15 m

So, the potential energy is

By substituting the values

U = 4.27 x 10^-14 J

(3) mass, m = 1 u = 1.67 x 10^-27 kg

So, the kinetic energy is equal to the potential energy.

Let v be the velocity.

v = 7.14 x 10^6 m/s

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2