Atruck covers 40.0 m in 7.45 s while uniformly slowing down to a final velocity of 3.50 m/s.
(a) find its original speed.
(b) find its acceleration

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be  

Explanation:

We have given distance covers by truck s = 40 m

Time taken by truck to cover this distance t = 7.45 sec

Final velocity v = 3.50 sec

According to second equation of motion

-----eqn 1

According to first equation of motion

v = u + at

So -----eqn2

Solving equation 1 and 2

a =

And u = 7.244 m /sec

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be

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