Two point-charges exert a 5 n force on each other. what will the force become if the distance between them is increased by a factor of three?

Force of attraction of repulsion between two charges bodies is given by Coulomb's law as,

k = Coulomb's Constant

Charge of the bodies

r = Distance

If the distance r is increased by 3 times then new force between charges is

The first force is given, then if we again replace the force we have that,

Therefore the final force will be 0.556N

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.