What quantity of heat is required to raise the temperature of 0.1 kg of water by 1⁰c

0.418 Joules

Explanation:

Recall that the formula :

Heat Added = Specific heat x mass x change in temperature

or

Q = mcΔT

in this case we are given that m = 0.1 kg, ΔT = 1°C  (aka 1 kelvin).

we also know that c for water is 4.1813 J/kg-K

substituting this into the formula

Q = 0.1 x 4.1813 x 1 = 0.41813 = 0.418 Joules ( 3 dec pl)

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )