This figure shows the angular displacement of a pendulum on a planet with five times the earth's gravity. how long is the pendulum's string?

1.0 m

3.2 m

0.80 m

4.0 m

Explanation:

The period (time per cycle) is 1.0 s.  The gravity is 5g or 49 m/s².  Therefore:

T = 2π √(L / g)

1.0 s = 2π √(L / 49 m/s²)

L = 1.2 m

unbalanced force

explanation:

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle