For each release height, a gate was located at half the release height. explain why the bob does not appear to have half of its maximum speed at this point.

= √2

Explanation:

Let's use the law of conservation of energy, to find the speed at medium height

Starting point Higher

             Em₀ = U = m g y

Final point. Lower

              = K = 1/2 m v²

             Em₀ =  

             mg y = ½ m v²

             v = √ 2g y

For the average height y = h / 2

           v = √ 2 g h / 2 = (√ 2gh) √ ½

Let's divide the two relationships

          v / v_media = √ mgh / (√ mgh / √2)

          v / v_medio = √2

From here we see that the speed is lower

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.