A80kg cart goes around the inside of a vertical loop of a roller coaste. the radius of the loop is 5m and the cart moves at a speed of 8 m/s. what is the force exerted on the track on the cart?

F = 1024 N

Explanation:

Given that,

Mass of the cart, m = 80 kg

Radius of the loop, r = 5 m

Speed of the cart, v = 8 m/s

To find,

the force exerted on the track on the cart.

Solution,

The force exerted on the track on the cart is called centripetal force. When an object moves in a circular path it possess centripetal force. It is given by :

F = 1024 N

So, the  force exerted on the track on the cart is 1024 N.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

it becomes positively charged by charging it