An antelope moving with constant acceleration covers the distance between two points 70.0 m apart in 6.00 s. its speed as it passes the second point is 15.0 m/s. what are (a) its speed at the first point and (b) its acceleration?

(a) 8.33m/s

(b) 1.11m/s^2

Explanation:

By using the equation of motion for the problem,

Given that V=15m/s U=?(unknown) t=6.0s S= 70m

By definition, distance is the product of the average velocity and time

From S=[(u+v)/2]xt

By substitution, 70 =[(U+15)/2]x 6

U=8.33m/s

By using V=U+at

15=6.66+6a

By substitution, acceleration=1.11m/s^2

1/0.14nm = 10^10/1.4 a lot