Arocket is fired vertically upward. at the instant it reaches some altitude with a speed of 100 m/s. it explodes into three fragments having equal mass. one fragment moves upward with a speed of 150 m/s following the explosion. the second fragment has a speed of 150 m/s and is moving east right after the explosion. what is the velocity of the third fragment immediately after the explosion?

The magnitude of the velocity of the third fragment  is 212.13 m/s.

Explanation:

Given that,

Speed = 100 m/s

Vertical speed of first fragment = 150 m/s

Vertical speed of second fragment = 150 m/s

We need to calculate the vertical speed of third fragment

Using conservation of momentum

Put the value into the formula

We need to calculate the horizontal speed of third fragment

Using conservation of momentum

Put the value into the formula

We need to calculate the magnitude of the velocity of the third fragment

Put the value into the formula

Hence, The magnitude of the velocity of the third fragment  is 212.13 m/s.

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explanation:

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