Physics, 19.01.2020 20:31 rose3358

(our
,
5. george walks to a friend's house. he walks 750 meters north, then realizes he walked too far. he
turns around and walks 250 meters south. the entire walk takes him 13 seconds. what is his speed
per second?
780m od north
you wild
) 250ml south
135 t
ooo m/135
76.923 m/s
6. in problem #5, what was george's velocity in meters per second? (hint: draw a picture to find his
displacement)

Answers: 2

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Answer from: plshelpme53

George's speed per second is 76.92 m/s

George's velocity in meters per second was 38.46 m/s (North)

Explanation:

When dividing the total distance covered by object by time, we get the value for average speed.

$\text { speed }=\frac{\text {distance}}{\text {time}}$

Given:

t = 13 seconds

Calculate the distance without consideration of motion’s direction. So, the distance walks 750 m north first, and then turn around walks 250 m south, so the total distance covered is

d = 750 + 250 = 1000 meters

To find the rate per second, simply divide the distance by the time.

$\text { speed }=\frac{1000}{13}=76.92 \mathrm{m} / \mathrm{s}$

In given case, the students walks 750 m north first, and then turn around walk 250 m south. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is

d = 750 (north) - 250 (south) = 500 m (north)

The time taken is t = 13 s

So, the average velocity is $\text {velocity}=\frac{500}{13}=38.46 \mathrm{m} / \mathrm{s}$ (North)

And the direction is north (the same as the displacement).

Answer from: Quest

resonant frequency

Answer from: Quest

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

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