An air-track glider attached to a spring oscillates between the 13.0 cmcm mark and the 64.0 cmcm mark on the track. the glider completes 15.0 oscillations in 35.0 ss . what are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider

To solve this problem we will apply the concepts related to the Period such as the relationship between the time taken to make the oscillations, the frequency as the inverse of the period, the amplitude as the midpoint of the distance traveled and the linear velocity as the product between the velocity angular and amplitude, this is

PART A) The period would be defined by the time it takes to perform the 15 oscillations so the unit value would be

PART B) The frequency as the inverse of the period

PART C) The amplitude as the midpoint of the distance traveled

PART D) The linear velocity is the product between the amplitude and the angular frequency, then

Where

Therefore the linear velocity is

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.

at right angles to each other