4. a latch holding a cart in place, hanging high above the ground, breaks and the cart falls. the cart started from rest and is in free fall until it hits the ground.
a. what is the velocity after 3.2 s?

b. how far has the cart fallen at 3.2 s?

a) 31.4 m/s

b) 50.2 m

Explanation:

a) When an object is free falling, its speed is determined by the gravity force giving it acceleration. Equation for the velocity of free fall started from the rest is:

v = g • t

g - is gravitational acceleration which is 9.81 m/s^2, sometimes rounded to 10

t - is the time of free fall

So:

v = 9.81 m/s^2 • 3.2

v = 31.4 m/s ( if g is rounded to 10, then the velocity is 10 • 3.2 = 32 m/s)

b) To determine the distance crossed in free fall we use the equation:

s = v0 + gt^2/2

v0 - is the starting velocity (since object started fall from rest, its v0 is 0)

s = gt^2/2

s = 9.81 m/s^2 • 3.2^2 / 2

s = 50.2 m (if we round g to 10 then the distance is 10 • 3.2^2/2 = 51.2 meters)

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

there are no contact forces mentioned on the list of choices that you've provided.