Amarble runs off the edge of a table that is 1.5 m high and the marble lands 0.50 m from the base of the table. a. how much time does it take the marble to hit the ground? b. what was the velocity of the marble on the table?

t = 0.55[sg]; v = 0.9[m/s]

Explanation:

In order to solve this problem we must establish the initial conditions with which we can work.

y = initial elevation = - 1.5 [m]

x = landing distance = 0.5 [m]

We set "y" with a negative value, as this height is below the table level.

in the following equation (vy)o is equal to zero because there is no velocity in the y component.

therefore:

Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.

f is prop to m1xm2 double m1 double force