Four identical masses of 2.5 kg each are located at the corners of a square with 1.0-m sides. what is the net force on any one of the masses?

F=8.0*10^{-10}N

Explanation:

See the attached file for the masses distributions

The force between two masses at distance r is expressed as

since the masses are of the same value, the above formula can be reduce to

using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is

The force on the lower left corner of the mass due to the lower right side of the mass is

The force on the lower left corner of the mass due to the upper right side of the mass is

The net force can be express as

if we insert values we arrive at

if we solve for the magnitude, we arrive at

Hence the net force on one of the masses is

0.863333

86%

hope this

massxgravity x heght=weightxheight= pe

4900=490xh

h=10