An object is undergoing shm with period 0.300 s and amplitude 6.00 cm. at t = 0 the object is instantaneously at rest at x = 6.00 cm. calculate the time it takes the object to go from x = 6.00 cm to x = -1.50 cm

Time taken is 0.087 s

Solution:

As per the question:

Time period, T = 0.300 s

Amplitude, A = 6.00 cm

Now,

To calculate the time taken:

For SHM, we know that:

                              (1)

At x = 6.00 cm, the object comes to rest instantaneously at times t = 0.00 s

Thus from eqn (1), for x = 6.00  cm:

Thus at t = 0.00 s, x = 6.00 cm

Now,

Using eqn (1) for x = - 1.50 cm:

We know that:

Thus

Time taken by the object in moving from x = 6.00 cm to x = 1.50 cm:

t' - t = 0.087 - 0.00 = 0.087 s

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles

uio

explanation: