Physics, 23.01.2020 05:31 Schoolworkspace453

When the brakes are applied on a moving car, the direction of the friction force on the car is in the (same or opposite) direction to the velocity of the car.

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Answer from: zamawi17

the direction of the friction force on the car is in the same direction to the VELOCITY of the car.

Explanation:

When the brakes are applied on a moving car then the speed of the car reduces slowly. The slowing of speed and the stopping of car takes a certain time which is proportional to the force applied by the brakes.

The brakes when applied to the moving part on the axle of the vehicle be it either drum or the disc offers the resistance to the rotation of the wheels in the form of friction.

As we know that friction always acts in a direction opposite to the relative motion between the two surfaces. So does here in this case the friction of brakes acts in a direction tangentially opposite to the rotation at the point of application of the brakes.

Similarly, the friction between the tyres and the road acts in a direction tangentially opposite to the direction of the relative motion between the surfaces i.e. the tyres move backwards relative to the road surface and hence the friction acts in the forward direction and is in the same direction as the motion of the car.

Answer from: demi9646

same direction

Explanation:

When a car is moving on the road frictional force act opposite the direction of the velocity of the vehicle.

But when you apply the brake the wheel will have the tendency to stop but friction will oppose.

The friction force starts acting in the direction of motion.

Hence, when you apply the brake on the moving car the direction of the friction will be in the same direction of the velocity of the car.

Answer from: Quest

Liquid. good luck : )

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

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