Awater gun fires 5 squirts per second. the speed of the squirts is 15 m/s.
by how much distance is each consecutive squirt
separated?

3.75 m

Explanation:

5 squirts in 1 second

So, 1 squirt in 1/5 second which is 0.2 second.

The difference in timing of two consecutive squirt is 0.2 second, so

time (t) = 0.2 s.

speed (s) = 15 m/s

Distance of separation (d) = ?

Now, formula for distance is

d = s × t

d = 15 × 0.2

d = 3.75 m

their crystal patterns have been disrupted by stress

truck y has a greater velocity than truck x.