A1-kg rock is suspended by a massless string from one end of a

1-m measuring stick. what is the weight of the measuring stick if it is

balanced by a support force at the 0.25-m mark?

The weight of measuring stick is 9.8 N

Explanation:

given information:

the mass of the rock, = 1 kg

measuring stick, x =1 m

d = 0.25 m

to find the weight of measuring stick, we can use the following equation:

τ = Fd

τ = 0

- = 0

F_{r} = the force of the rock

F_{s} = the force of measuring stick

    = m g

    = 1 kg x 9.8 m/s

    = 9.8 N

thus, the weight of measuring stick is 9.8 N

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y