Ahelicopter is flying horizontally with a speed of 339 m/s over a hill that slopes upward with a 2% grade. what is the component of the helicopter's velocity perpendicular to the sloping surface of the hill?

We will use the trigonometric ratios to know the helicopter's deceleration speed. Later applying the concept of speed as a vector component of the value found we will find the vertical speed.

The 2% grade indicates that for every 100 meters traveled in the x direction, there is an ascent / descent of 2 meters. Therefore we will have the relationship

Now you would have the value of the angle tangent would be

From this relationship we could conclude that the vertical speed would be

Therefore the component of the helicopter's velocity perpendicular to the sloping surface of the hill is 6.78m/s

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach