An astronaut standing on a platform on the moon drops a hammer. if the hammer falls 6.0 meters vertically in 2.7 seconds, what is its acceleration? a. 1.6m/s²
b. 4.4m/s²
c. 2.2m/s²
d. 9.8m/s²

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Displacement, s = 6 m

        Time, t = 2.7 s      

     Substituting

                      s = ut + 0.5 at²

                      6 = 0 x 2.7 + 0.5 x a x 2.7²

                      a = 1.65 m/s²

Acceleration is 1.65 m/s²

Option A is the correct answer.

d) the number of neutrons plus the number of protons